112413312013 has 2 divisors, whose sum is σ = 112413312014. Its totient is φ = 112413312012.

The previous prime is 112413311951. The next prime is 112413312017. The reversal of 112413312013 is 310213314211.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 61661332489 + 50751979524 = 248317^2 + 225282^2 .

It is an emirp because it is prime and its reverse (310213314211) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-112413312013 is a prime.

It is a super-2 number, since 2×112413312013² (a number of 23 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (112413312017) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56206656006 + 56206656007.

It is an arithmetic number, because the mean of its divisors is an integer number (56206656007).

Almost surely, 2^112413312013 is an apocalyptic number.

It is an amenable number.

112413312013 is a deficient number, since it is larger than the sum of its proper divisors (1).

112413312013 is an equidigital number, since it uses as much as digits as its factorization.

112413312013 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 432, while the sum is 22.

Adding to 112413312013 its reverse (310213314211), we get a palindrome (422626626224).

The spelling of 112413312013 in words is "one hundred twelve billion, four hundred thirteen million, three hundred twelve thousand, thirteen".