Search a number
-
+
11241412001134 = 27802958000081
BaseRepresentation
bin1010001110010101100001…
…0111100111110101101110
31110210200001022220222201121
42203211120113213311232
52433134402433014014
635524122224331154
72240110445266450
oct243453027476556
943720038828647
1011241412001134
113644502014537
1213167b2173aba
136370a31b68c3
142ac13157c2d0
1514763557b124
hexa39585e7d6e

11241412001134 has 8 divisors (see below), whose sum is σ = 19270992001968. Its totient is φ = 4817748000480.

The previous prime is 11241412001107. The next prime is 11241412001191. The reversal of 11241412001134 is 43110021414211.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a junction number, because it is equal to n+sod(n) for n = 11241412001099 and 11241412001108.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 401479000027 + ... + 401479000054.

It is an arithmetic number, because the mean of its divisors is an integer number (2408874000246).

Almost surely, 211241412001134 is an apocalyptic number.

11241412001134 is a gapful number since it is divisible by the number (14) formed by its first and last digit.

11241412001134 is a deficient number, since it is larger than the sum of its proper divisors (8029580000834).

11241412001134 is an equidigital number, since it uses as much as digits as its factorization.

11241412001134 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 802958000090.

The product of its (nonzero) digits is 768, while the sum is 25.

Adding to 11241412001134 its reverse (43110021414211), we get a palindrome (54351433415345).

The spelling of 11241412001134 in words is "eleven trillion, two hundred forty-one billion, four hundred twelve million, one thousand, one hundred thirty-four".

Divisors: 1 2 7 14 802958000081 1605916000162 5620706000567 11241412001134