Base | Representation |
---|---|
bin | 110100010110001101… |
… | …0100100001101001001 |
3 | 101202011100100200202221 |
4 | 1220230122210031021 |
5 | 3320211030424431 |
6 | 123350432454041 |
7 | 11056505610511 |
oct | 1505432441511 |
9 | 352140320687 |
10 | 112414311241 |
11 | 43746a47961 |
12 | 199533aa321 |
13 | a7a675683b |
14 | 5625aca841 |
15 | 2dce049111 |
hex | 1a2c6a4349 |
112414311241 has 2 divisors, whose sum is σ = 112414311242. Its totient is φ = 112414311240.
The previous prime is 112414311161. The next prime is 112414311253. The reversal of 112414311241 is 142113414211.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 108435855616 + 3978455625 = 329296^2 + 63075^2 .
It is a cyclic number.
It is not a de Polignac number, because 112414311241 - 225 = 112380756809 is a prime.
It is a super-3 number, since 3×1124143112413 (a number of 34 digits) contains 333 as substring.
It is not a weakly prime, because it can be changed into another prime (112414311271) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56207155620 + 56207155621.
It is an arithmetic number, because the mean of its divisors is an integer number (56207155621).
Almost surely, 2112414311241 is an apocalyptic number.
It is an amenable number.
112414311241 is a deficient number, since it is larger than the sum of its proper divisors (1).
112414311241 is an equidigital number, since it uses as much as digits as its factorization.
112414311241 is an evil number, because the sum of its binary digits is even.
The product of its digits is 768, while the sum is 25.
Adding to 112414311241 its reverse (142113414211), we get a palindrome (254527725452).
The spelling of 112414311241 in words is "one hundred twelve billion, four hundred fourteen million, three hundred eleven thousand, two hundred forty-one".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.070 sec. • engine limits •