Base | Representation |
---|---|
bin | 10000010111000000001… |
… | …110000000000010011111 |
3 | 10222110210020000021201012 |
4 | 100113000032000002133 |
5 | 121404341102004103 |
6 | 2220242223005435 |
7 | 144136001614442 |
oct | 20270016000237 |
9 | 3873706007635 |
10 | 1124211359903 |
11 | 3a3859006045 |
12 | 161a6813987b |
13 | 82021b08438 |
14 | 3c5aac01659 |
15 | 1e39b2e22d8 |
hex | 105c038009f |
1124211359903 has 2 divisors, whose sum is σ = 1124211359904. Its totient is φ = 1124211359902.
The previous prime is 1124211359899. The next prime is 1124211359941. The reversal of 1124211359903 is 3099531124211.
It is a weak prime.
It is an emirp because it is prime and its reverse (3099531124211) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 1124211359903 - 22 = 1124211359899 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1124211359003) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 562105679951 + 562105679952.
It is an arithmetic number, because the mean of its divisors is an integer number (562105679952).
Almost surely, 21124211359903 is an apocalyptic number.
1124211359903 is a deficient number, since it is larger than the sum of its proper divisors (1).
1124211359903 is an equidigital number, since it uses as much as digits as its factorization.
1124211359903 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 58320, while the sum is 41.
The spelling of 1124211359903 in words is "one trillion, one hundred twenty-four billion, two hundred eleven million, three hundred fifty-nine thousand, nine hundred three".
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