Base | Representation |
---|---|
bin | 10000010111000000010… |
… | …100110001000000011101 |
3 | 10222110210100100101102002 |
4 | 100113000110301000131 |
5 | 121404342030231331 |
6 | 2220242325012045 |
7 | 144136022652014 |
oct | 20270024610035 |
9 | 3873710311362 |
10 | 1124213133341 |
11 | 3a385a0074a1 |
12 | 161a68854025 |
13 | 820222a96cc |
14 | 3c5ab143a7b |
15 | 1e39b5429cb |
hex | 105c053101d |
1124213133341 has 2 divisors, whose sum is σ = 1124213133342. Its totient is φ = 1124213133340.
The previous prime is 1124213133311. The next prime is 1124213133353. The reversal of 1124213133341 is 1433313124211.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1075130503225 + 49082630116 = 1036885^2 + 221546^2 .
It is a cyclic number.
It is not a de Polignac number, because 1124213133341 - 222 = 1124208939037 is a prime.
It is a Sophie Germain prime.
It is a Curzon number.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1124213133311) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 562106566670 + 562106566671.
It is an arithmetic number, because the mean of its divisors is an integer number (562106566671).
Almost surely, 21124213133341 is an apocalyptic number.
It is an amenable number.
1124213133341 is a deficient number, since it is larger than the sum of its proper divisors (1).
1124213133341 is an equidigital number, since it uses as much as digits as its factorization.
1124213133341 is an evil number, because the sum of its binary digits is even.
The product of its digits is 5184, while the sum is 29.
Adding to 1124213133341 its reverse (1433313124211), we get a palindrome (2557526257552).
The spelling of 1124213133341 in words is "one trillion, one hundred twenty-four billion, two hundred thirteen million, one hundred thirty-three thousand, three hundred forty-one".
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