Base | Representation |
---|---|
bin | 110100010110011101… |
… | …1101110100100110111 |
3 | 101202011221201100122102 |
4 | 1220230323232210313 |
5 | 3320220242120341 |
6 | 123351343052315 |
7 | 11056642525301 |
oct | 1505473564467 |
9 | 352157640572 |
10 | 112423004471 |
11 | 43750945248 |
12 | 199562a109b |
13 | a7a84ab66b |
14 | 5626d10971 |
15 | 2dcebb4c9b |
hex | 1a2ceee937 |
112423004471 has 2 divisors, whose sum is σ = 112423004472. Its totient is φ = 112423004470.
The previous prime is 112423004431. The next prime is 112423004501. The reversal of 112423004471 is 174400324211.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 112423004471 - 222 = 112418810167 is a prime.
It is a super-3 number, since 3×1124230044713 (a number of 34 digits) contains 333 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (112423004431) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56211502235 + 56211502236.
It is an arithmetic number, because the mean of its divisors is an integer number (56211502236).
Almost surely, 2112423004471 is an apocalyptic number.
112423004471 is a deficient number, since it is larger than the sum of its proper divisors (1).
112423004471 is an equidigital number, since it uses as much as digits as its factorization.
112423004471 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 5376, while the sum is 29.
Adding to 112423004471 its reverse (174400324211), we get a palindrome (286823328682).
The spelling of 112423004471 in words is "one hundred twelve billion, four hundred twenty-three million, four thousand, four hundred seventy-one".
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