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11242401202031 is a prime number
BaseRepresentation
bin1010001110011001001101…
…0101000111111101101111
31110210202121021021121020212
42203212103111013331233
52433143414201431111
635524404322333035
72240144116332206
oct243462325077557
943722537247225
1011242401202031
11364496a43183a
121316a294ba17b
1363720011258c
142ac1c6ab823d
1514769232798b
hexa3993547f6f

11242401202031 has 2 divisors, whose sum is σ = 11242401202032. Its totient is φ = 11242401202030.

The previous prime is 11242401202013. The next prime is 11242401202051. The reversal of 11242401202031 is 13020210424211.

Together with previous prime (11242401202013) it forms an Ormiston pair, because they use the same digits, order apart.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 11242401202031 - 226 = 11242334093167 is a prime.

It is a super-2 number, since 2×112424012020312 (a number of 27 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 11242401201988 and 11242401202006.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11242401202051) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5621200601015 + 5621200601016.

It is an arithmetic number, because the mean of its divisors is an integer number (5621200601016).

Almost surely, 211242401202031 is an apocalyptic number.

11242401202031 is a deficient number, since it is larger than the sum of its proper divisors (1).

11242401202031 is an equidigital number, since it uses as much as digits as its factorization.

11242401202031 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 768, while the sum is 23.

Adding to 11242401202031 its reverse (13020210424211), we get a palindrome (24262611626242).

The spelling of 11242401202031 in words is "eleven trillion, two hundred forty-two billion, four hundred one million, two hundred two thousand, thirty-one".