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1124325333137 is a prime number
BaseRepresentation
bin10000010111000111000…
…000110001100010010001
310222111002011110201121002
4100113013000301202101
5121410104241130022
62220301413511345
7144141554435066
oct20270700614221
93874064421532
101124325333137
113a39073808a6
12161a9a342555
138203c602116
143c5bbdccc6d
151e3a6307092
hex105c7031891

1124325333137 has 2 divisors, whose sum is σ = 1124325333138. Its totient is φ = 1124325333136.

The previous prime is 1124325333097. The next prime is 1124325333149. The reversal of 1124325333137 is 7313335234211.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 803158308481 + 321167024656 = 896191^2 + 566716^2 .

It is a cyclic number.

It is not a de Polignac number, because 1124325333137 - 26 = 1124325333073 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 1124325333137.

It is not a weakly prime, because it can be changed into another prime (1124325333167) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 562162666568 + 562162666569.

It is an arithmetic number, because the mean of its divisors is an integer number (562162666569).

Almost surely, 21124325333137 is an apocalyptic number.

It is an amenable number.

1124325333137 is a deficient number, since it is larger than the sum of its proper divisors (1).

1124325333137 is an equidigital number, since it uses as much as digits as its factorization.

1124325333137 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 136080, while the sum is 38.

The spelling of 1124325333137 in words is "one trillion, one hundred twenty-four billion, three hundred twenty-five million, three hundred thirty-three thousand, one hundred thirty-seven".