Base | Representation |
---|---|
bin | 11001100100001000100011… |
… | …110101001000001001101111 |
3 | 112202002121110112210111222212 |
4 | 121210020203311020021233 |
5 | 104214110323240114041 |
6 | 1035043330024401035 |
7 | 32453051436615014 |
oct | 3144104365101157 |
9 | 482077415714885 |
10 | 112434255004271 |
11 | 32909110882062 |
12 | 1073a61861617b |
13 | 4a97673c32a55 |
14 | 1da9bc017170b |
15 | ceea165598eb |
hex | 664223d4826f |
112434255004271 has 2 divisors, whose sum is σ = 112434255004272. Its totient is φ = 112434255004270.
The previous prime is 112434255004259. The next prime is 112434255004277. The reversal of 112434255004271 is 172400552434211.
It is a strong prime.
It is an emirp because it is prime and its reverse (172400552434211) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 112434255004271 - 218 = 112434254742127 is a prime.
It is a Sophie Germain prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (112434255004277) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56217127502135 + 56217127502136.
It is an arithmetic number, because the mean of its divisors is an integer number (56217127502136).
Almost surely, 2112434255004271 is an apocalyptic number.
112434255004271 is a deficient number, since it is larger than the sum of its proper divisors (1).
112434255004271 is an equidigital number, since it uses as much as digits as its factorization.
112434255004271 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 268800, while the sum is 41.
The spelling of 112434255004271 in words is "one hundred twelve trillion, four hundred thirty-four billion, two hundred fifty-five million, four thousand, two hundred seventy-one".
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