Base | Representation |
---|---|
bin | 10100111100010110… |
… | …00011110111000001 |
3 | 1002000120212210102002 |
4 | 22132023003313001 |
5 | 141011332242423 |
6 | 5055410033345 |
7 | 545425212245 |
oct | 123613036701 |
9 | 32016783362 |
10 | 11243634113 |
11 | 484a8137a8 |
12 | 2219578855 |
13 | 10a254b64a |
14 | 7893b0425 |
15 | 45c167228 |
hex | 29e2c3dc1 |
11243634113 has 2 divisors, whose sum is σ = 11243634114. Its totient is φ = 11243634112.
The previous prime is 11243634089. The next prime is 11243634223. The reversal of 11243634113 is 31143634211.
It is a happy number.
11243634113 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 6814997809 + 4428636304 = 82553^2 + 66548^2 .
It is a cyclic number.
It is not a de Polignac number, because 11243634113 - 218 = 11243371969 is a prime.
It is not a weakly prime, because it can be changed into another prime (11243634013) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5621817056 + 5621817057.
It is an arithmetic number, because the mean of its divisors is an integer number (5621817057).
Almost surely, 211243634113 is an apocalyptic number.
It is an amenable number.
11243634113 is a deficient number, since it is larger than the sum of its proper divisors (1).
11243634113 is an equidigital number, since it uses as much as digits as its factorization.
11243634113 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 5184, while the sum is 29.
The spelling of 11243634113 in words is "eleven billion, two hundred forty-three million, six hundred thirty-four thousand, one hundred thirteen".
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