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1124401443133 is a prime number
BaseRepresentation
bin10000010111001011100…
…011000111000100111101
310222111021110200111212211
4100113023203013010331
5121410233232140013
62220313133100421
7144143500400113
oct20271343070475
93874243614784
101124401443133
113a3946335421
12161abb927711
13820522cca17
143c5c8161ab3
151e3acd3d23d
hex105cb8c713d

1124401443133 has 2 divisors, whose sum is σ = 1124401443134. Its totient is φ = 1124401443132.

The previous prime is 1124401443071. The next prime is 1124401443197. The reversal of 1124401443133 is 3313441044211.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 918632153209 + 205769289924 = 958453^2 + 453618^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1124401443133 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1124401443095 and 1124401443104.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1124401440133) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 562200721566 + 562200721567.

It is an arithmetic number, because the mean of its divisors is an integer number (562200721567).

Almost surely, 21124401443133 is an apocalyptic number.

It is an amenable number.

1124401443133 is a deficient number, since it is larger than the sum of its proper divisors (1).

1124401443133 is an equidigital number, since it uses as much as digits as its factorization.

1124401443133 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 13824, while the sum is 31.

Adding to 1124401443133 its reverse (3313441044211), we get a palindrome (4437842487344).

The spelling of 1124401443133 in words is "one trillion, one hundred twenty-four billion, four hundred one million, four hundred forty-three thousand, one hundred thirty-three".