Base | Representation |
---|---|
bin | 10000010111001011100… |
… | …110100010100011100001 |
3 | 10222111021112101012001101 |
4 | 100113023212202203201 |
5 | 121410233444421423 |
6 | 2220313204234401 |
7 | 144143511133051 |
oct | 20271346424341 |
9 | 3874245335041 |
10 | 1124402342113 |
11 | 3a3946899886 |
12 | 161b0009ba01 |
13 | 82052555c6b |
14 | 3c5c8317561 |
15 | 1e3ace697ad |
hex | 105cb9a28e1 |
1124402342113 has 2 divisors, whose sum is σ = 1124402342114. Its totient is φ = 1124402342112.
The previous prime is 1124402342101. The next prime is 1124402342117. The reversal of 1124402342113 is 3112432044211.
It is a happy number.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1036796405824 + 87605936289 = 1018232^2 + 295983^2 .
It is a cyclic number.
It is not a de Polignac number, because 1124402342113 - 237 = 986963388641 is a prime.
It is not a weakly prime, because it can be changed into another prime (1124402342117) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 562201171056 + 562201171057.
It is an arithmetic number, because the mean of its divisors is an integer number (562201171057).
Almost surely, 21124402342113 is an apocalyptic number.
It is an amenable number.
1124402342113 is a deficient number, since it is larger than the sum of its proper divisors (1).
1124402342113 is an equidigital number, since it uses as much as digits as its factorization.
1124402342113 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 4608, while the sum is 28.
Adding to 1124402342113 its reverse (3112432044211), we get a palindrome (4236834386324).
The spelling of 1124402342113 in words is "one trillion, one hundred twenty-four billion, four hundred two million, three hundred forty-two thousand, one hundred thirteen".
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