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11244043451 is a prime number
BaseRepresentation
bin10100111100011001…
…00111110010111011
31002000121122120220202
422132030213302323
5141011433342301
65055422512415
7545431535534
oct123614476273
932017576822
1011244043451
11484aa732a3
12221973570b
1310a2662a64
1478947968b
1545c1e866b
hex29e327cbb

11244043451 has 2 divisors, whose sum is σ = 11244043452. Its totient is φ = 11244043450.

The previous prime is 11244043411. The next prime is 11244043453. The reversal of 11244043451 is 15434044211.

It is a strong prime.

It is an emirp because it is prime and its reverse (15434044211) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-11244043451 is a prime.

It is a Sophie Germain prime.

Together with 11244043453, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (11244043453) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5622021725 + 5622021726.

It is an arithmetic number, because the mean of its divisors is an integer number (5622021726).

Almost surely, 211244043451 is an apocalyptic number.

11244043451 is a deficient number, since it is larger than the sum of its proper divisors (1).

11244043451 is an equidigital number, since it uses as much as digits as its factorization.

11244043451 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 7680, while the sum is 29.

Adding to 11244043451 its reverse (15434044211), we get a palindrome (26678087662).

The spelling of 11244043451 in words is "eleven billion, two hundred forty-four million, forty-three thousand, four hundred fifty-one".