Base | Representation |
---|---|
bin | 1010001110100011000000… |
… | …1101001011110000110111 |
3 | 1110211000101200202002000000 |
4 | 2203220300031023300313 |
5 | 2433214311441041401 |
6 | 35525521422122343 |
7 | 2240266255425420 |
oct | 243506015136067 |
9 | 43730350662000 |
10 | 11245033143351 |
11 | 3645aa0063257 |
12 | 1317442a203b3 |
13 | 63752c489cc7 |
14 | 2ac396472647 |
15 | 147798417186 |
hex | a3a3034bc37 |
11245033143351 has 112 divisors (see below), whose sum is σ = 19638109587456. Its totient is φ = 6302511903168.
The previous prime is 11245033143349. The next prime is 11245033143353. The reversal of 11245033143351 is 15334133054211.
11245033143351 is a `hidden beast` number, since 1 + 1 + 2 + 4 + 5 + 0 + 3 + 314 + 335 + 1 = 666.
It is an interprime number because it is at equal distance from previous prime (11245033143349) and next prime (11245033143353).
It is not a de Polignac number, because 11245033143351 - 21 = 11245033143349 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (11245033143353) by changing a digit.
It is a polite number, since it can be written in 111 ways as a sum of consecutive naturals, for example, 1482922906 + ... + 1482930488.
Almost surely, 211245033143351 is an apocalyptic number.
11245033143351 is a deficient number, since it is larger than the sum of its proper divisors (8393076444105).
11245033143351 is an frugal number, since it uses more digits than its factorization.
11245033143351 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 13144 (or 13129 counting only the distinct ones).
The product of its (nonzero) digits is 64800, while the sum is 36.
Adding to 11245033143351 its reverse (15334133054211), we get a palindrome (26579166197562).
The spelling of 11245033143351 in words is "eleven trillion, two hundred forty-five billion, thirty-three million, one hundred forty-three thousand, three hundred fifty-one".
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