Base | Representation |
---|---|
bin | 10000010111010100011… |
… | …110100011011010101001 |
3 | 10222111122220120011021002 |
4 | 100113110132203122221 |
5 | 121411040104242213 |
6 | 2220340043524345 |
7 | 144150266565512 |
oct | 20272436433251 |
9 | 3874586504232 |
10 | 1124551243433 |
11 | 3a3a12950622 |
12 | 161b41b296b5 |
13 | 8207735ba57 |
14 | 3c5dddd7a09 |
15 | 1e3bb07d658 |
hex | 105d47a36a9 |
1124551243433 has 2 divisors, whose sum is σ = 1124551243434. Its totient is φ = 1124551243432.
The previous prime is 1124551243421. The next prime is 1124551243441. The reversal of 1124551243433 is 3343421554211.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1044163116649 + 80388126784 = 1021843^2 + 283528^2 .
It is a cyclic number.
It is not a de Polignac number, because 1124551243433 - 212 = 1124551239337 is a prime.
It is a Sophie Germain prime.
It is a Curzon number.
It is not a weakly prime, because it can be changed into another prime (1124551243463) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 562275621716 + 562275621717.
It is an arithmetic number, because the mean of its divisors is an integer number (562275621717).
Almost surely, 21124551243433 is an apocalyptic number.
It is an amenable number.
1124551243433 is a deficient number, since it is larger than the sum of its proper divisors (1).
1124551243433 is an equidigital number, since it uses as much as digits as its factorization.
1124551243433 is an evil number, because the sum of its binary digits is even.
The product of its digits is 172800, while the sum is 38.
Adding to 1124551243433 its reverse (3343421554211), we get a palindrome (4467972797644).
The spelling of 1124551243433 in words is "one trillion, one hundred twenty-four billion, five hundred fifty-one million, two hundred forty-three thousand, four hundred thirty-three".
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