Base | Representation |
---|---|
bin | 1010001110101110011110… |
… | …1101000011011001011111 |
3 | 1110211022100020122101111221 |
4 | 2203223213231003121133 |
5 | 2433242113100300343 |
6 | 35531151114554211 |
7 | 2240435460111466 |
oct | 243534755033137 |
9 | 43738306571457 |
10 | 11248111728223 |
11 | 364732a918677 |
12 | 1317b61a38967 |
13 | 637900227766 |
14 | 2ac5a92939dd |
15 | 1478c88305ed |
hex | a3ae7b4365f |
11248111728223 has 2 divisors, whose sum is σ = 11248111728224. Its totient is φ = 11248111728222.
The previous prime is 11248111728193. The next prime is 11248111728263. The reversal of 11248111728223 is 32282711184211.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 11248111728223 - 213 = 11248111720031 is a prime.
It is a super-3 number, since 3×112481117282233 (a number of 40 digits) contains 333 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 11248111728223.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11248111728263) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5624055864111 + 5624055864112.
It is an arithmetic number, because the mean of its divisors is an integer number (5624055864112).
Almost surely, 211248111728223 is an apocalyptic number.
11248111728223 is a deficient number, since it is larger than the sum of its proper divisors (1).
11248111728223 is an equidigital number, since it uses as much as digits as its factorization.
11248111728223 is an evil number, because the sum of its binary digits is even.
The product of its digits is 86016, while the sum is 43.
The spelling of 11248111728223 in words is "eleven trillion, two hundred forty-eight billion, one hundred eleven million, seven hundred twenty-eight thousand, two hundred twenty-three".
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