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1125014145433 is a prime number
BaseRepresentation
bin10000010111110000000…
…100011000100110011001
310222112212011121000102121
4100113300010120212121
5121413012110123213
62220454021301241
7144164620312153
oct20276004304631
93875764530377
101125014145433
113a4130179762
12162050b64821
138211c225169
143c645693ad3
151e3e6a1988d
hex105f0118999

1125014145433 has 2 divisors, whose sum is σ = 1125014145434. Its totient is φ = 1125014145432.

The previous prime is 1125014145427. The next prime is 1125014145443. The reversal of 1125014145433 is 3345414105211.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 691738197264 + 433275948169 = 831708^2 + 658237^2 .

It is an emirp because it is prime and its reverse (3345414105211) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1125014145433 - 217 = 1125014014361 is a prime.

It is not a weakly prime, because it can be changed into another prime (1125014145403) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 562507072716 + 562507072717.

It is an arithmetic number, because the mean of its divisors is an integer number (562507072717).

Almost surely, 21125014145433 is an apocalyptic number.

It is an amenable number.

1125014145433 is a deficient number, since it is larger than the sum of its proper divisors (1).

1125014145433 is an equidigital number, since it uses as much as digits as its factorization.

1125014145433 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 28800, while the sum is 34.

The spelling of 1125014145433 in words is "one trillion, one hundred twenty-five billion, fourteen million, one hundred forty-five thousand, four hundred thirty-three".