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112502443980713 is a prime number
BaseRepresentation
bin11001100101001000000100…
…001101011011011110101001
3112202100010110202101102120212
4121211020010031123132221
5104221220001124340323
61035134524223030505
732461014303425423
oct3145100415333651
9482303422342525
10112502443980713
1132935022770346
121074b888a3b435
134aa0c200ca917
141dad20c441813
15d016a7b85b78
hex66520435b7a9

112502443980713 has 2 divisors, whose sum is σ = 112502443980714. Its totient is φ = 112502443980712.

The previous prime is 112502443980691. The next prime is 112502443980739. The reversal of 112502443980713 is 317089344205211.

It is a happy number.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 112072648354969 + 429795625744 = 10586437^2 + 655588^2 .

It is an emirp because it is prime and its reverse (317089344205211) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-112502443980713 is a prime.

It is not a weakly prime, because it can be changed into another prime (112502443980763) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56251221990356 + 56251221990357.

It is an arithmetic number, because the mean of its divisors is an integer number (56251221990357).

Almost surely, 2112502443980713 is an apocalyptic number.

It is an amenable number.

112502443980713 is a deficient number, since it is larger than the sum of its proper divisors (1).

112502443980713 is an equidigital number, since it uses as much as digits as its factorization.

112502443980713 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1451520, while the sum is 50.

The spelling of 112502443980713 in words is "one hundred twelve trillion, five hundred two billion, four hundred forty-three million, nine hundred eighty thousand, seven hundred thirteen".