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112513142032 = 247032071377
BaseRepresentation
bin110100011001001001…
…1100100110100010000
3101202102020022211010121
41220302103210310100
53320411331021112
6123404323040024
711062115633104
oct1506223446420
9352366284117
10112513142032
114379780a9a5
1219980510014
13a7c107b0b5
145634c95904
152dd7a6c407
hex1a324e4d10

112513142032 has 10 divisors (see below), whose sum is σ = 217994212718. Its totient is φ = 56256571008.

The previous prime is 112513142017. The next prime is 112513142081. The reversal of 112513142032 is 230241315211.

112513142032 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.

It can be written as a sum of positive squares in only one way, i.e., 93920183296 + 18592958736 = 306464^2 + 136356^2 .

It is a junction number, because it is equal to n+sod(n) for n = 112513141988 and 112513142006.

It is an unprimeable number.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3516035673 + ... + 3516035704.

Almost surely, 2112513142032 is an apocalyptic number.

It is an amenable number.

112513142032 is a deficient number, since it is larger than the sum of its proper divisors (105481070686).

112513142032 is an equidigital number, since it uses as much as digits as its factorization.

112513142032 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 7032071385 (or 7032071379 counting only the distinct ones).

The product of its (nonzero) digits is 1440, while the sum is 25.

Adding to 112513142032 its reverse (230241315211), we get a palindrome (342754457243).

The spelling of 112513142032 in words is "one hundred twelve billion, five hundred thirteen million, one hundred forty-two thousand, thirty-two".

Divisors: 1 2 4 8 16 7032071377 14064142754 28128285508 56256571016 112513142032