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1125134553377 is a prime number
BaseRepresentation
bin10000010111110111001…
…111101101000100100001
310222120011120011101002002
4100113313033231010201
5121413233421202002
62220514002133345
7144200611622552
oct20276717550441
93876146141062
101125134553377
113a4192139a5a
12162085351255
138213b162973
143c657678329
151e4023a1002
hex105f73ed121

1125134553377 has 2 divisors, whose sum is σ = 1125134553378. Its totient is φ = 1125134553376.

The previous prime is 1125134553331. The next prime is 1125134553383. The reversal of 1125134553377 is 7733554315211.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 764463440896 + 360671112481 = 874336^2 + 600559^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1125134553377 is a prime.

It is a super-2 number, since 2×11251345533772 (a number of 25 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (1125134553307) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 562567276688 + 562567276689.

It is an arithmetic number, because the mean of its divisors is an integer number (562567276689).

Almost surely, 21125134553377 is an apocalyptic number.

It is an amenable number.

1125134553377 is a deficient number, since it is larger than the sum of its proper divisors (1).

1125134553377 is an equidigital number, since it uses as much as digits as its factorization.

1125134553377 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 1323000, while the sum is 47.

Adding to 1125134553377 its reverse (7733554315211), we get a palindrome (8858688868588).

The spelling of 1125134553377 in words is "one trillion, one hundred twenty-five billion, one hundred thirty-four million, five hundred fifty-three thousand, three hundred seventy-seven".