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112515402861353 is a prime number
BaseRepresentation
bin11001100101010100001000…
…100111101000101100101001
3112202101100220212210202220002
4121211110020213220230221
5104221423021113030403
61035144510144512345
732461653400203512
oct3145241047505451
9482340825722802
10112515402861353
113293a572710158
12107522a491b6b5
134aa2206b0342b
141dadabb545a09
15d01bb56b4188
hex6655089e8b29

112515402861353 has 2 divisors, whose sum is σ = 112515402861354. Its totient is φ = 112515402861352.

The previous prime is 112515402861319. The next prime is 112515402861361. The reversal of 112515402861353 is 353168204515211.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 111850147301929 + 665255559424 = 10575923^2 + 815632^2 .

It is a cyclic number.

It is not a de Polignac number, because 112515402861353 - 232 = 112511107894057 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 112515402861298 and 112515402861307.

It is not a weakly prime, because it can be changed into another prime (112515402861383) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56257701430676 + 56257701430677.

It is an arithmetic number, because the mean of its divisors is an integer number (56257701430677).

Almost surely, 2112515402861353 is an apocalyptic number.

It is an amenable number.

112515402861353 is a deficient number, since it is larger than the sum of its proper divisors (1).

112515402861353 is an equidigital number, since it uses as much as digits as its factorization.

112515402861353 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 864000, while the sum is 47.

The spelling of 112515402861353 in words is "one hundred twelve trillion, five hundred fifteen billion, four hundred two million, eight hundred sixty-one thousand, three hundred fifty-three".