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112523757113 is a prime number
BaseRepresentation
bin110100011001011110…
…0000100011000111001
3101202102222022010021202
41220302330010120321
53320422040211423
6123405342343545
711062305103625
oct1506274043071
9352388263252
10112523757113
11437a2800199
1219983b8abb5
13a7c3326901
14563645a185
152dd8967728
hex1a32f04639

112523757113 has 2 divisors, whose sum is σ = 112523757114. Its totient is φ = 112523757112.

The previous prime is 112523757109. The next prime is 112523757139. The reversal of 112523757113 is 311757325211.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 112474378384 + 49378729 = 335372^2 + 7027^2 .

It is an emirp because it is prime and its reverse (311757325211) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 112523757113 - 22 = 112523757109 is a prime.

It is a super-4 number, since 4×1125237571134 (a number of 45 digits) contains 4444 as substring.

It is not a weakly prime, because it can be changed into another prime (112523757103) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56261878556 + 56261878557.

It is an arithmetic number, because the mean of its divisors is an integer number (56261878557).

Almost surely, 2112523757113 is an apocalyptic number.

It is an amenable number.

112523757113 is a deficient number, since it is larger than the sum of its proper divisors (1).

112523757113 is an equidigital number, since it uses as much as digits as its factorization.

112523757113 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 44100, while the sum is 38.

The spelling of 112523757113 in words is "one hundred twelve billion, five hundred twenty-three million, seven hundred fifty-seven thousand, one hundred thirteen".