Base | Representation |
---|---|
bin | 110100011001011110… |
… | …1000000100001001111 |
3 | 101202102222202122010202 |
4 | 1220302331000201033 |
5 | 3320422121102112 |
6 | 123405351524115 |
7 | 11062310150654 |
oct | 1506275004117 |
9 | 352388678122 |
10 | 112524003407 |
11 | 437a2959242 |
12 | 1998408963b |
13 | a7c33b1a4a |
14 | 56364c1c2b |
15 | 2dd89b56c2 |
hex | 1a32f4084f |
112524003407 has 2 divisors, whose sum is σ = 112524003408. Its totient is φ = 112524003406.
The previous prime is 112524003377. The next prime is 112524003419. The reversal of 112524003407 is 704300425211.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-112524003407 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 112524003407.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (112524003457) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56262001703 + 56262001704.
It is an arithmetic number, because the mean of its divisors is an integer number (56262001704).
Almost surely, 2112524003407 is an apocalyptic number.
112524003407 is a deficient number, since it is larger than the sum of its proper divisors (1).
112524003407 is an equidigital number, since it uses as much as digits as its factorization.
112524003407 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 6720, while the sum is 29.
Adding to 112524003407 its reverse (704300425211), we get a palindrome (816824428618).
The spelling of 112524003407 in words is "one hundred twelve billion, five hundred twenty-four million, three thousand, four hundred seven".
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