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11254041014141 is a prime number
BaseRepresentation
bin1010001111000100100100…
…0111011110111101111101
31110211212122110122022201002
42203301021013132331331
52433341233444423031
635534011324100045
72241035425160402
oct243611107367575
943755573568632
1011254041014141
1136498a283a972
121319137694625
13638336764973
142ac9ac9362a9
15147b2414accb
hexa3c491def7d

11254041014141 has 2 divisors, whose sum is σ = 11254041014142. Its totient is φ = 11254041014140.

The previous prime is 11254041014137. The next prime is 11254041014207. The reversal of 11254041014141 is 14141014045211.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 5860248432025 + 5393792582116 = 2420795^2 + 2322454^2 .

It is a cyclic number.

It is not a de Polignac number, because 11254041014141 - 22 = 11254041014137 is a prime.

It is a Sophie Germain prime.

It is a Curzon number.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11254041314141) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5627020507070 + 5627020507071.

It is an arithmetic number, because the mean of its divisors is an integer number (5627020507071).

Almost surely, 211254041014141 is an apocalyptic number.

It is an amenable number.

11254041014141 is a deficient number, since it is larger than the sum of its proper divisors (1).

11254041014141 is an equidigital number, since it uses as much as digits as its factorization.

11254041014141 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 2560, while the sum is 29.

Adding to 11254041014141 its reverse (14141014045211), we get a palindrome (25395055059352).

The spelling of 11254041014141 in words is "eleven trillion, two hundred fifty-four billion, forty-one million, fourteen thousand, one hundred forty-one".