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11254044253 is a prime number
BaseRepresentation
bin10100111101100101…
…10001011001011101
31002001022110200102211
422132302301121131
5141022013404003
65100421120421
7545612540434
oct123662613135
932038420384
1011254044253
114855684021
122220b59111
1310a4754aaa
1478a92011b
1545d02196d
hex29ecb165d

11254044253 has 2 divisors, whose sum is σ = 11254044254. Its totient is φ = 11254044252.

The previous prime is 11254044229. The next prime is 11254044257. The reversal of 11254044253 is 35244045211.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 10491290329 + 762753924 = 102427^2 + 27618^2 .

It is an emirp because it is prime and its reverse (35244045211) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-11254044253 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11254044257) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5627022126 + 5627022127.

It is an arithmetic number, because the mean of its divisors is an integer number (5627022127).

Almost surely, 211254044253 is an apocalyptic number.

It is an amenable number.

11254044253 is a deficient number, since it is larger than the sum of its proper divisors (1).

11254044253 is an equidigital number, since it uses as much as digits as its factorization.

11254044253 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 19200, while the sum is 31.

Adding to 11254044253 its reverse (35244045211), we get a palindrome (46498089464).

The spelling of 11254044253 in words is "eleven billion, two hundred fifty-four million, forty-four thousand, two hundred fifty-three".