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11254114330 = 251125411433
BaseRepresentation
bin10100111101100110…
…00010100000011010
31002001022121020120021
422132303002200122
5141022023124310
65100422421054
7545613251644
oct123663024032
932038536507
1011254114330
114855721738
122220b9178a
1310a477a964
1478a93b894
1545d0375da
hex29ecc281a

11254114330 has 8 divisors (see below), whose sum is σ = 20257405812. Its totient is φ = 4501645728.

The previous prime is 11254114321. The next prime is 11254114379. The reversal of 11254114330 is 3341145211.

It can be written as a sum of positive squares in 2 ways, for example, as 11055050449 + 199063881 = 105143^2 + 14109^2 .

It is a sphenic number, since it is the product of 3 distinct primes.

It is a super-2 number, since 2×112541143302 (a number of 21 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 11254114295 and 11254114304.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 562705707 + ... + 562705726.

Almost surely, 211254114330 is an apocalyptic number.

11254114330 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

11254114330 is a deficient number, since it is larger than the sum of its proper divisors (9003291482).

11254114330 is a wasteful number, since it uses less digits than its factorization.

11254114330 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1125411440.

The product of its (nonzero) digits is 1440, while the sum is 25.

Adding to 11254114330 its reverse (3341145211), we get a palindrome (14595259541).

The spelling of 11254114330 in words is "eleven billion, two hundred fifty-four million, one hundred fourteen thousand, three hundred thirty".

Divisors: 1 2 5 10 1125411433 2250822866 5627057165 11254114330