Base | Representation |
---|---|
bin | 110100011010000011… |
… | …0101010010110000001 |
3 | 101202111100002120111102 |
4 | 1220310012222112001 |
5 | 3320442041424413 |
6 | 123411321424145 |
7 | 11062633235003 |
oct | 1506406522601 |
9 | 352440076442 |
10 | 112543311233 |
11 | 43802846521 |
12 | 1998a63b055 |
13 | a7c73b20b2 |
14 | 5638caa373 |
15 | 2dda52b458 |
hex | 1a341aa581 |
112543311233 has 2 divisors, whose sum is σ = 112543311234. Its totient is φ = 112543311232.
The previous prime is 112543311161. The next prime is 112543311241. The reversal of 112543311233 is 332113345211.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 87209177344 + 25334133889 = 295312^2 + 159167^2 .
It is an emirp because it is prime and its reverse (332113345211) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 112543311233 - 214 = 112543294849 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 112543311196 and 112543311205.
It is not a weakly prime, because it can be changed into another prime (112543311733) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56271655616 + 56271655617.
It is an arithmetic number, because the mean of its divisors is an integer number (56271655617).
Almost surely, 2112543311233 is an apocalyptic number.
It is an amenable number.
112543311233 is a deficient number, since it is larger than the sum of its proper divisors (1).
112543311233 is an equidigital number, since it uses as much as digits as its factorization.
112543311233 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 6480, while the sum is 29.
Adding to 112543311233 its reverse (332113345211), we get a palindrome (444656656444).
The spelling of 112543311233 in words is "one hundred twelve billion, five hundred forty-three million, three hundred eleven thousand, two hundred thirty-three".
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