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112550130000 = 243254711109149
BaseRepresentation
bin110100011010010000…
…0101011000101010000
3101202111210221000002100
41220310200223011100
53321000313130000
6123412123520400
711063045214540
oct1506440530520
9352453830070
10112550130000
1143806683570
1219990989100
13a7c892b979
145639b63320
152ddae26a00
hex1a3482b150

112550130000 has 1200 divisors, whose sum is σ = 498552912000. Its totient is φ = 23016960000.

The previous prime is 112550129983. The next prime is 112550130001. The reversal of 112550130000 is 31055211.

112550130000 is a `hidden beast` number, since 112 + 550 + 1 + 3 + 0 + 0 + 0 + 0 = 666.

It is a tau number, because it is divible by the number of its divisors (1200).

It is a Harshad number since it is a multiple of its sum of digits (18).

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (112550130001) by changing a digit.

It is a polite number, since it can be written in 239 ways as a sum of consecutive naturals, for example, 755369926 + ... + 755370074.

It is an arithmetic number, because the mean of its divisors is an integer number (415460760).

Almost surely, 2112550130000 is an apocalyptic number.

112550130000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 112550130000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (249276456000).

112550130000 is an abundant number, since it is smaller than the sum of its proper divisors (386002782000).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

112550130000 is a wasteful number, since it uses less digits than its factorization.

112550130000 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 310 (or 286 counting only the distinct ones).

The product of its (nonzero) digits is 150, while the sum is 18.

Adding to 112550130000 its reverse (31055211), we get a palindrome (112581185211).

The spelling of 112550130000 in words is "one hundred twelve billion, five hundred fifty million, one hundred thirty thousand".