Base | Representation |
---|---|
bin | 1010001111001010001100… |
… | …1111101110100100111011 |
3 | 1110212000112211221111101122 |
4 | 2203302203033232210323 |
5 | 2433402333044442132 |
6 | 35534421341535455 |
7 | 2241121045665035 |
oct | 243624317564473 |
9 | 43760484844348 |
10 | 11255553124667 |
11 | 364a4a9341995 |
12 | 1319499b7458b |
13 | 638517b07317 |
14 | 2acab36acc55 |
15 | 147bb1c88912 |
hex | a3ca33ee93b |
11255553124667 has 2 divisors, whose sum is σ = 11255553124668. Its totient is φ = 11255553124666.
The previous prime is 11255553124619. The next prime is 11255553124721. The reversal of 11255553124667 is 76642135555211.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-11255553124667 is a prime.
It is a super-2 number, since 2×112555531246672 (a number of 27 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (11255553124367) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5627776562333 + 5627776562334.
It is an arithmetic number, because the mean of its divisors is an integer number (5627776562334).
Almost surely, 211255553124667 is an apocalyptic number.
11255553124667 is a deficient number, since it is larger than the sum of its proper divisors (1).
11255553124667 is an equidigital number, since it uses as much as digits as its factorization.
11255553124667 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 7560000, while the sum is 53.
Adding to 11255553124667 its reverse (76642135555211), we get a palindrome (87897688679878).
The spelling of 11255553124667 in words is "eleven trillion, two hundred fifty-five billion, five hundred fifty-three million, one hundred twenty-four thousand, six hundred sixty-seven".
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