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11255654051441 is a prime number
BaseRepresentation
bin1010001111001010100101…
…0000101110111001110001
31110212000210212212002220022
42203302221100232321301
52433403034414121231
635534435345053225
72241123412600142
oct243625120567161
943760725762808
1011255654051441
11364a550306748
121319507927215
136385329b38c7
142acac2c61ac9
15147bbaa72c7b
hexa3ca942ee71

11255654051441 has 2 divisors, whose sum is σ = 11255654051442. Its totient is φ = 11255654051440.

The previous prime is 11255654051437. The next prime is 11255654051471. The reversal of 11255654051441 is 14415045655211.

It is a happy number.

11255654051441 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 6885376000000 + 4370278051441 = 2624000^2 + 2090521^2 .

It is a cyclic number.

It is not a de Polignac number, because 11255654051441 - 22 = 11255654051437 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 11255654051392 and 11255654051401.

It is not a weakly prime, because it can be changed into another prime (11255654051471) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5627827025720 + 5627827025721.

It is an arithmetic number, because the mean of its divisors is an integer number (5627827025721).

Almost surely, 211255654051441 is an apocalyptic number.

It is an amenable number.

11255654051441 is a deficient number, since it is larger than the sum of its proper divisors (1).

11255654051441 is an equidigital number, since it uses as much as digits as its factorization.

11255654051441 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 480000, while the sum is 44.

The spelling of 11255654051441 in words is "eleven trillion, two hundred fifty-five billion, six hundred fifty-four million, fifty-one thousand, four hundred forty-one".