Base | Representation |
---|---|
bin | 10100111101110011… |
… | …11111111101110111 |
3 | 1002001110000221110020 |
4 | 22132321333331313 |
5 | 141023010021220 |
6 | 5100525500223 |
7 | 545634621333 |
oct | 123671777567 |
9 | 32043027406 |
10 | 11255938935 |
11 | 485675857a |
12 | 2221711673 |
13 | 10a4c692c7 |
14 | 78ac947c3 |
15 | 45d298040 |
hex | 29ee7ff77 |
11255938935 has 32 divisors (see below), whose sum is σ = 19074631680. Its totient is φ = 5648337408.
The previous prime is 11255938933. The next prime is 11255938949. The reversal of 11255938935 is 53983955211.
It is not a de Polignac number, because 11255938935 - 21 = 11255938933 is a prime.
It is a super-2 number, since 2×112559389352 (a number of 21 digits) contains 22 as substring.
It is a Harshad number since it is a multiple of its sum of digits (51).
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (11255938933) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 1613986 + ... + 1620944.
It is an arithmetic number, because the mean of its divisors is an integer number (596082240).
Almost surely, 211255938935 is an apocalyptic number.
11255938935 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
11255938935 is a deficient number, since it is larger than the sum of its proper divisors (7818692745).
11255938935 is a wasteful number, since it uses less digits than its factorization.
11255938935 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 13327.
The product of its digits is 1458000, while the sum is 51.
The spelling of 11255938935 in words is "eleven billion, two hundred fifty-five million, nine hundred thirty-eight thousand, nine hundred thirty-five".
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