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11259001133557 is a prime number
BaseRepresentation
bin1010001111010111000011…
…0000110101100111110101
31110212100110010222111101121
42203311300300311213311
52433431413242233212
635540151432423541
72241302354405062
oct243656060654765
943770403874347
1011259001133557
113650a08689011
12131a0a0847bb1
1363894726c178
142acd1d5b5c69
15147d14825d07
hexa3d70c359f5

11259001133557 has 2 divisors, whose sum is σ = 11259001133558. Its totient is φ = 11259001133556.

The previous prime is 11259001133537. The next prime is 11259001133573. The reversal of 11259001133557 is 75533110095211.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 5718033520081 + 5540967613476 = 2391241^2 + 2353926^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-11259001133557 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11259001133537) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5629500566778 + 5629500566779.

It is an arithmetic number, because the mean of its divisors is an integer number (5629500566779).

Almost surely, 211259001133557 is an apocalyptic number.

It is an amenable number.

11259001133557 is a deficient number, since it is larger than the sum of its proper divisors (1).

11259001133557 is an equidigital number, since it uses as much as digits as its factorization.

11259001133557 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 141750, while the sum is 43.

The spelling of 11259001133557 in words is "eleven trillion, two hundred fifty-nine billion, one million, one hundred thirty-three thousand, five hundred fifty-seven".