Base | Representation |
---|---|
bin | 1010001111101001010010… |
… | …0100111010100001111111 |
3 | 1110212211002100022222211222 |
4 | 2203322110210322201333 |
5 | 2434021430110030012 |
6 | 35542321323103555 |
7 | 2241534603245024 |
oct | 243722444724177 |
9 | 43784070288758 |
10 | 11263896955007 |
11 | 3652aa0200144 |
12 | 131b028371bbb |
13 | 639247653338 |
14 | 2ad2658b954b |
15 | 147eee54e972 |
hex | a3e9493a87f |
11263896955007 has 2 divisors, whose sum is σ = 11263896955008. Its totient is φ = 11263896955006.
The previous prime is 11263896954977. The next prime is 11263896955033. The reversal of 11263896955007 is 70055969836211.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 11263896955007 - 218 = 11263896692863 is a prime.
It is a super-3 number, since 3×112638969550073 (a number of 40 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11263896955057) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5631948477503 + 5631948477504.
It is an arithmetic number, because the mean of its divisors is an integer number (5631948477504).
Almost surely, 211263896955007 is an apocalyptic number.
11263896955007 is a deficient number, since it is larger than the sum of its proper divisors (1).
11263896955007 is an equidigital number, since it uses as much as digits as its factorization.
11263896955007 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 24494400, while the sum is 62.
The spelling of 11263896955007 in words is "eleven trillion, two hundred sixty-three billion, eight hundred ninety-six million, nine hundred fifty-five thousand, seven".
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