Base | Representation |
---|---|
bin | 11001101010000101001000… |
… | …010010001111001110101011 |
3 | 112210112200012220211100002022 |
4 | 121222011020102033032223 |
5 | 104242304213424231311 |
6 | 1035555150214455055 |
7 | 32524425654236552 |
oct | 3152051022171653 |
9 | 483480186740068 |
10 | 112842888508331 |
11 | 32a56444833883 |
12 | 107a585b06448b |
13 | 4ac7067110977 |
14 | 1dc18a6bc6d99 |
15 | d0a480d885db |
hex | 66a14848f3ab |
112842888508331 has 2 divisors, whose sum is σ = 112842888508332. Its totient is φ = 112842888508330.
The previous prime is 112842888508307. The next prime is 112842888508333. The reversal of 112842888508331 is 133805888248211.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-112842888508331 is a prime.
It is a super-2 number, since 2×1128428885083312 (a number of 29 digits) contains 22 as substring.
Together with 112842888508333, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (112842888508333) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56421444254165 + 56421444254166.
It is an arithmetic number, because the mean of its divisors is an integer number (56421444254166).
Almost surely, 2112842888508331 is an apocalyptic number.
112842888508331 is a deficient number, since it is larger than the sum of its proper divisors (1).
112842888508331 is an equidigital number, since it uses as much as digits as its factorization.
112842888508331 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 23592960, while the sum is 62.
The spelling of 112842888508331 in words is "one hundred twelve trillion, eight hundred forty-two billion, eight hundred eighty-eight million, five hundred eight thousand, three hundred thirty-one".
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