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11284423920013 is a prime number
BaseRepresentation
bin1010010000110101110000…
…0101000100100110001101
31110221210001220102212012011
42210031130011010212031
52434341000010420023
635555554235141221
72243162354464036
oct244153405044615
943853056385164
1011284423920013
113660774133832
121322bb68a4811
1363b16926478a
142b0251b75a8d
151488016ad50d
hexa435c14498d

11284423920013 has 2 divisors, whose sum is σ = 11284423920014. Its totient is φ = 11284423920012.

The previous prime is 11284423919971. The next prime is 11284423920023. The reversal of 11284423920013 is 31002932448211.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 7379681934249 + 3904741985764 = 2716557^2 + 1976042^2 .

It is a cyclic number.

It is not a de Polignac number, because 11284423920013 - 229 = 11283887049101 is a prime.

It is a super-3 number, since 3×112844239200133 (a number of 40 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11284423920023) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5642211960006 + 5642211960007.

It is an arithmetic number, because the mean of its divisors is an integer number (5642211960007).

Almost surely, 211284423920013 is an apocalyptic number.

It is an amenable number.

11284423920013 is a deficient number, since it is larger than the sum of its proper divisors (1).

11284423920013 is an equidigital number, since it uses as much as digits as its factorization.

11284423920013 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 82944, while the sum is 40.

The spelling of 11284423920013 in words is "eleven trillion, two hundred eighty-four billion, four hundred twenty-three million, nine hundred twenty thousand, thirteen".