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112970114833 is a prime number
BaseRepresentation
bin110100100110110001…
…0110010011100010001
3101210121002012102222011
41221031202302130101
53322330322133313
6123521525342521
711106335063242
oct1511542623421
9353532172864
10112970114833
1143a01759374
1219a89567a41
13a8649497c4
14567984acc9
152e12c3693d
hex1a4d8b2711

112970114833 has 2 divisors, whose sum is σ = 112970114834. Its totient is φ = 112970114832.

The previous prime is 112970114701. The next prime is 112970114849. The reversal of 112970114833 is 338411079211.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 106437757504 + 6532357329 = 326248^2 + 80823^2 .

It is a cyclic number.

It is not a de Polignac number, because 112970114833 - 221 = 112968017681 is a prime.

It is not a weakly prime, because it can be changed into another prime (112970114233) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56485057416 + 56485057417.

It is an arithmetic number, because the mean of its divisors is an integer number (56485057417).

Almost surely, 2112970114833 is an apocalyptic number.

It is an amenable number.

112970114833 is a deficient number, since it is larger than the sum of its proper divisors (1).

112970114833 is an equidigital number, since it uses as much as digits as its factorization.

112970114833 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 36288, while the sum is 40.

The spelling of 112970114833 in words is "one hundred twelve billion, nine hundred seventy million, one hundred fourteen thousand, eight hundred thirty-three".