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112989433 is a prime number
BaseRepresentation
bin1101011110000…
…01010011111001
321212121110100211
412233001103321
5212411130213
615113431121
72541252154
oct657012371
9255543324
10112989433
11588636a7
1231a0b4a1
131a540c6b
1411012c9b
159dbd53d
hex6bc14f9

112989433 has 2 divisors, whose sum is σ = 112989434. Its totient is φ = 112989432.

The previous prime is 112989427. The next prime is 112989439. The reversal of 112989433 is 334989211.

It is a balanced prime because it is at equal distance from previous prime (112989427) and next prime (112989439).

It can be written as a sum of positive squares in only one way, i.e., 72641529 + 40347904 = 8523^2 + 6352^2 .

It is an emirp because it is prime and its reverse (334989211) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 112989433 - 221 = 110892281 is a prime.

It is a super-2 number, since 2×1129894332 = 25533223939322978, which contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (112989439) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56494716 + 56494717.

It is an arithmetic number, because the mean of its divisors is an integer number (56494717).

Almost surely, 2112989433 is an apocalyptic number.

It is an amenable number.

112989433 is a deficient number, since it is larger than the sum of its proper divisors (1).

112989433 is an equidigital number, since it uses as much as digits as its factorization.

112989433 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 46656, while the sum is 40.

The square root of 112989433 is about 10629.6487712436. The cubic root of 112989433 is about 483.4437423025.

The spelling of 112989433 in words is "one hundred twelve million, nine hundred eighty-nine thousand, four hundred thirty-three".