Base | Representation |
---|---|
bin | 1010010001101111111000… |
… | …0000000101110101011101 |
3 | 1111000021100012102102221021 |
4 | 2210123332000011311131 |
5 | 2440114423002101440 |
6 | 40011054321404141 |
7 | 2244254110212034 |
oct | 244337600056535 |
9 | 44007305372837 |
10 | 11300025425245 |
11 | 366734a841607 |
12 | 132602b799651 |
13 | 63c7845b558b |
14 | 2b0cd1c1571b |
15 | 148e161db84a |
hex | a46fe005d5d |
11300025425245 has 4 divisors (see below), whose sum is σ = 13560030510300. Its totient is φ = 9040020340192.
The previous prime is 11300025425207. The next prime is 11300025425287. The reversal of 11300025425245 is 54252452000311.
It is a happy number.
11300025425245 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in 2 ways, for example, as 3800604836196 + 7499420589049 = 1949514^2 + 2738507^2 .
It is a cyclic number.
It is not a de Polignac number, because 11300025425245 - 213 = 11300025417053 is a prime.
It is a super-2 number, since 2×113000254252452 (a number of 27 digits) contains 22 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 11300025425245.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1130002542520 + ... + 1130002542529.
It is an arithmetic number, because the mean of its divisors is an integer number (3390007627575).
Almost surely, 211300025425245 is an apocalyptic number.
It is an amenable number.
11300025425245 is a deficient number, since it is larger than the sum of its proper divisors (2260005085055).
11300025425245 is an equidigital number, since it uses as much as digits as its factorization.
11300025425245 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2260005085054.
The product of its (nonzero) digits is 48000, while the sum is 34.
Adding to 11300025425245 its reverse (54252452000311), we get a palindrome (65552477425556).
The spelling of 11300025425245 in words is "eleven trillion, three hundred billion, twenty-five million, four hundred twenty-five thousand, two hundred forty-five".
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