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113001101230 = 2511300110123
BaseRepresentation
bin110100100111101100…
…0111111011110101110
3101210200020111201022111
41221033120333132232
53322411240214410
6123524553434234
711110162340503
oct1511730773656
9353606451274
10113001101230
1143a181a2966
1219a97a0b97a
13a86b1a8754
14567d9d54aa
152e15807b8a
hex1a4f63f7ae

113001101230 has 8 divisors (see below), whose sum is σ = 203401982232. Its totient is φ = 45200440488.

The previous prime is 113001101173. The next prime is 113001101231. The reversal of 113001101230 is 32101100311.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a self number, because there is not a number n which added to its sum of digits gives 113001101230.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (113001101231) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5650055052 + ... + 5650055071.

It is an arithmetic number, because the mean of its divisors is an integer number (25425247779).

Almost surely, 2113001101230 is an apocalyptic number.

113001101230 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

113001101230 is a deficient number, since it is larger than the sum of its proper divisors (90400881002).

113001101230 is a wasteful number, since it uses less digits than its factorization.

113001101230 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 11300110130.

The product of its (nonzero) digits is 18, while the sum is 13.

Adding to 113001101230 its reverse (32101100311), we get a palindrome (145102201541).

The spelling of 113001101230 in words is "one hundred thirteen billion, one million, one hundred one thousand, two hundred thirty".

Divisors: 1 2 5 10 11300110123 22600220246 56500550615 113001101230