Base | Representation |
---|---|
bin | 11001101100011000011111… |
… | …000101001110001100101010 |
3 | 112211002210121201101201221022 |
4 | 121230120133011032030222 |
5 | 104302402233410122310 |
6 | 1040155554352212442 |
7 | 32542026605346161 |
oct | 3154303705161452 |
9 | 484083551351838 |
10 | 113001111020330 |
11 | 33007558268995 |
12 | 1081045753a122 |
13 | 4b08c61040130 |
14 | 1dc93d66043d8 |
15 | d0e641767a55 |
hex | 66c61f14e32a |
113001111020330 has 128 divisors (see below), whose sum is σ = 220499655667200. Its totient is φ = 41448251649024.
The previous prime is 113001111020321. The next prime is 113001111020381. The reversal of 113001111020330 is 33020111100311.
It is a junction number, because it is equal to n+sod(n) for n = 113001111020299 and 113001111020308.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 13836301907 + ... + 13836310073.
It is an arithmetic number, because the mean of its divisors is an integer number (1722653559900).
Almost surely, 2113001111020330 is an apocalyptic number.
113001111020330 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
113001111020330 is a deficient number, since it is larger than the sum of its proper divisors (107498544646870).
113001111020330 is a wasteful number, since it uses less digits than its factorization.
113001111020330 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 9648.
The product of its (nonzero) digits is 54, while the sum is 17.
Adding to 113001111020330 its reverse (33020111100311), we get a palindrome (146021222120641).
The spelling of 113001111020330 in words is "one hundred thirteen trillion, one billion, one hundred eleven million, twenty thousand, three hundred thirty".
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