Base | Representation |
---|---|
bin | 11001101100011000011111… |
… | …000110010101001101111011 |
3 | 112211002210121201221111222021 |
4 | 121230120133012111031323 |
5 | 104302402233443424402 |
6 | 1040155554402335311 |
7 | 32542026611000236 |
oct | 3154303706251573 |
9 | 484083551844867 |
10 | 113001111311227 |
11 | 330075584474a7 |
12 | 1081045765a537 |
13 | 4b08c61112669 |
14 | 1dc93d667c41d |
15 | d0e6417c3d37 |
hex | 66c61f19537b |
113001111311227 has 2 divisors, whose sum is σ = 113001111311228. Its totient is φ = 113001111311226.
The previous prime is 113001111311203. The next prime is 113001111311237. The reversal of 113001111311227 is 722113111100311.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-113001111311227 is a prime.
It is not a weakly prime, because it can be changed into another prime (113001111311237) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 56500555655613 + 56500555655614.
It is an arithmetic number, because the mean of its divisors is an integer number (56500555655614).
Almost surely, 2113001111311227 is an apocalyptic number.
113001111311227 is a deficient number, since it is larger than the sum of its proper divisors (1).
113001111311227 is an equidigital number, since it uses as much as digits as its factorization.
113001111311227 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 252, while the sum is 25.
Adding to 113001111311227 its reverse (722113111100311), we get a palindrome (835114222411538).
The spelling of 113001111311227 in words is "one hundred thirteen trillion, one billion, one hundred eleven million, three hundred eleven thousand, two hundred twenty-seven".
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