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1130011321212 = 223429211587971
BaseRepresentation
bin10000011100011001111…
…011000110001101111100
311000000202102122211220000
4100130121323012031330
5122003230344234322
62223041532154300
7144432506514564
oct20343173061574
94000672584800
101130011321212
113a6264a278a4
12163006608990
13827376053c7
143c99b21bda4
151e5da5b43ac
hex10719ec637c

1130011321212 has 240 divisors, whose sum is σ = 3078818709120. Its totient is φ = 360969436800.

The previous prime is 1130011321189. The next prime is 1130011321237. The reversal of 1130011321212 is 2121231100311.

1130011321212 is a `hidden beast` number, since 1 + 130 + 0 + 1 + 1 + 321 + 212 = 666.

It is a super-2 number, since 2×11300113212122 (a number of 25 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (18).

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 79 ways as a sum of consecutive naturals, for example, 1163759887 + ... + 1163760857.

It is an arithmetic number, because the mean of its divisors is an integer number (12828411288).

Almost surely, 21130011321212 is an apocalyptic number.

1130011321212 is a gapful number since it is divisible by the number (12) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 1130011321212, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (1539409354560).

1130011321212 is an abundant number, since it is smaller than the sum of its proper divisors (1948807387908).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

1130011321212 is a wasteful number, since it uses less digits than its factorization.

1130011321212 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1814 (or 1803 counting only the distinct ones).

The product of its (nonzero) digits is 72, while the sum is 18.

Adding to 1130011321212 its reverse (2121231100311), we get a palindrome (3251242421523).

The spelling of 1130011321212 in words is "one trillion, one hundred thirty billion, eleven million, three hundred twenty-one thousand, two hundred twelve".