Base | Representation |
---|---|
bin | 10000011100011001111… |
… | …011000110001110010101 |
3 | 11000000202102122211220221 |
4 | 100130121323012032111 |
5 | 122003230344234422 |
6 | 2223041532154341 |
7 | 144432506514631 |
oct | 20343173061625 |
9 | 4000672584827 |
10 | 1130011321237 |
11 | 3a6264a27917 |
12 | 1630066089b1 |
13 | 82737605416 |
14 | 3c99b21bdc1 |
15 | 1e5da5b43c7 |
hex | 10719ec6395 |
1130011321237 has 2 divisors, whose sum is σ = 1130011321238. Its totient is φ = 1130011321236.
The previous prime is 1130011321189. The next prime is 1130011321249. The reversal of 1130011321237 is 7321231100311.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 913236341956 + 216774979281 = 955634^2 + 465591^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1130011321237 is a prime.
It is a super-2 number, since 2×11300113212372 (a number of 25 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1130011321267) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 565005660618 + 565005660619.
It is an arithmetic number, because the mean of its divisors is an integer number (565005660619).
Almost surely, 21130011321237 is an apocalyptic number.
It is an amenable number.
1130011321237 is a deficient number, since it is larger than the sum of its proper divisors (1).
1130011321237 is an equidigital number, since it uses as much as digits as its factorization.
1130011321237 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 756, while the sum is 25.
Adding to 1130011321237 its reverse (7321231100311), we get a palindrome (8451242421548).
The spelling of 1130011321237 in words is "one trillion, one hundred thirty billion, eleven million, three hundred twenty-one thousand, two hundred thirty-seven".
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