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1130011321237 is a prime number
BaseRepresentation
bin10000011100011001111…
…011000110001110010101
311000000202102122211220221
4100130121323012032111
5122003230344234422
62223041532154341
7144432506514631
oct20343173061625
94000672584827
101130011321237
113a6264a27917
121630066089b1
1382737605416
143c99b21bdc1
151e5da5b43c7
hex10719ec6395

1130011321237 has 2 divisors, whose sum is σ = 1130011321238. Its totient is φ = 1130011321236.

The previous prime is 1130011321189. The next prime is 1130011321249. The reversal of 1130011321237 is 7321231100311.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 913236341956 + 216774979281 = 955634^2 + 465591^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1130011321237 is a prime.

It is a super-2 number, since 2×11300113212372 (a number of 25 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1130011321267) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 565005660618 + 565005660619.

It is an arithmetic number, because the mean of its divisors is an integer number (565005660619).

Almost surely, 21130011321237 is an apocalyptic number.

It is an amenable number.

1130011321237 is a deficient number, since it is larger than the sum of its proper divisors (1).

1130011321237 is an equidigital number, since it uses as much as digits as its factorization.

1130011321237 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 756, while the sum is 25.

Adding to 1130011321237 its reverse (7321231100311), we get a palindrome (8451242421548).

The spelling of 1130011321237 in words is "one trillion, one hundred thirty billion, eleven million, three hundred twenty-one thousand, two hundred thirty-seven".