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1130013130310 = 25367130782161
BaseRepresentation
bin10000011100011010000…
…001111111111001000110
311000000202120001202111122
4100130122001333321012
5122003231330132220
62223042035033542
7144432531061121
oct20343201777106
94000676052448
101130013130310
113a6265a53019
1216300713b8b2
1382737ab998c
143c99b56d3b8
151e5da820425
hex1071a07fe46

1130013130310 has 16 divisors (see below), whose sum is σ = 2034577779552. Its totient is φ = 451882108800.

The previous prime is 1130013130237. The next prime is 1130013130321. The reversal of 1130013130310 is 130313100311.

It is a super-2 number, since 2×11300131303102 (a number of 25 digits) contains 22 as substring.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 15354371 + ... + 15427790.

It is an arithmetic number, because the mean of its divisors is an integer number (127161111222).

Almost surely, 21130013130310 is an apocalyptic number.

1130013130310 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

1130013130310 is a deficient number, since it is larger than the sum of its proper divisors (904564649242).

1130013130310 is a wasteful number, since it uses less digits than its factorization.

1130013130310 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 30785839.

The product of its (nonzero) digits is 81, while the sum is 17.

Adding to 1130013130310 its reverse (130313100311), we get a palindrome (1260326230621).

Subtracting from 1130013130310 its reverse (130313100311), we obtain a cube (999700029999 = 99993).

The spelling of 1130013130310 in words is "one trillion, one hundred thirty billion, thirteen million, one hundred thirty thousand, three hundred ten".

Divisors: 1 2 5 10 3671 7342 18355 36710 30782161 61564322 153910805 307821610 113001313031 226002626062 565006565155 1130013130310