Base | Representation |
---|---|
bin | 1010010001110000010001… |
… | …0111110101010001000110 |
3 | 1111000021121122112212011221 |
4 | 2210130010113311101012 |
5 | 2440120132332442014 |
6 | 40011113100350554 |
7 | 2244256545556441 |
oct | 244340427652106 |
9 | 44007548485157 |
10 | 11300132312134 |
11 | 36673a5107286 |
12 | 132605b54545a |
13 | 63c7a079a963 |
14 | 2b0d020ba658 |
15 | 148e207a1b24 |
hex | a47045f5446 |
11300132312134 has 8 divisors (see below), whose sum is σ = 16950224376360. Its totient is φ = 5650057520016.
The previous prime is 11300132312011. The next prime is 11300132312153. The reversal of 11300132312134 is 43121323100311.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a junction number, because it is equal to n+sod(n) for n = 11300132312099 and 11300132312108.
It is a congruent number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2535204 + ... + 5387719.
It is an arithmetic number, because the mean of its divisors is an integer number (2118778047045).
Almost surely, 211300132312134 is an apocalyptic number.
11300132312134 is a deficient number, since it is larger than the sum of its proper divisors (5650092064226).
11300132312134 is an equidigital number, since it uses as much as digits as its factorization.
11300132312134 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 8636054.
The product of its (nonzero) digits is 1296, while the sum is 25.
Adding to 11300132312134 its reverse (43121323100311), we get a palindrome (54421455412445).
The spelling of 11300132312134 in words is "eleven trillion, three hundred billion, one hundred thirty-two million, three hundred twelve thousand, one hundred thirty-four".
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