1130015125121 has 2 divisors, whose sum is σ = 1130015125122. Its totient is φ = 1130015125120.

The previous prime is 1130015125013. The next prime is 1130015125123. The reversal of 1130015125121 is 1215215100311.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1118329515121 + 11685610000 = 1057511^2 + 108100^2 .

It is a cyclic number.

It is not a de Polignac number, because 1130015125121 - 2¹⁴ = 1130015108737 is a prime.

Together with 1130015125123, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (1130015125123) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 565007562560 + 565007562561.

It is an arithmetic number, because the mean of its divisors is an integer number (565007562561).

Almost surely, 2^{1130015125121} is an apocalyptic number.

It is an amenable number.

1130015125121 is a deficient number, since it is larger than the sum of its proper divisors (1).

1130015125121 is an equidigital number, since it uses as much as digits as its factorization.

1130015125121 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 300, while the sum is 23.

The spelling of 1130015125121 in words is "one trillion, one hundred thirty billion, fifteen million, one hundred twenty-five thousand, one hundred twenty-one".