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113002111300 = 225213701124001
BaseRepresentation
bin110100100111101110…
…0110110000101000100
3101210200022102000212111
41221033130312011010
53322412020030200
6123525031230404
711110204045351
oct1511734660504
9353608360774
10113002111300
1143a18822831
1219a98218404
13a86b470420
14567dbb9628
152e159570ba
hex1a4f736144

113002111300 has 72 divisors (see below), whose sum is σ = 264456089352. Its totient is φ = 41664000000.

The previous prime is 113002111297. The next prime is 113002111309. The reversal of 113002111300 is 3111200311.

It can be written as a sum of positive squares in 12 ways, for example, as 42245047296 + 70757064004 = 205536^2 + 266002^2 .

It is a Harshad number since it is a multiple of its sum of digits (13).

It is not an unprimeable number, because it can be changed into a prime (113002111309) by changing a digit.

It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 849300 + ... + 973300.

It is an arithmetic number, because the mean of its divisors is an integer number (3673001241).

Almost surely, 2113002111300 is an apocalyptic number.

113002111300 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 113002111300, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (132228044676).

113002111300 is an abundant number, since it is smaller than the sum of its proper divisors (151453978052).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

113002111300 is a wasteful number, since it uses less digits than its factorization.

113002111300 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 124729 (or 124722 counting only the distinct ones).

The product of its (nonzero) digits is 18, while the sum is 13.

Adding to 113002111300 its reverse (3111200311), we get a palindrome (116113311611).

The spelling of 113002111300 in words is "one hundred thirteen billion, two million, one hundred eleven thousand, three hundred".

Divisors: 1 2 4 5 10 13 20 25 26 50 52 65 100 130 260 325 650 701 1300 1402 2804 3505 7010 9113 14020 17525 18226 35050 36452 45565 70100 91130 124001 182260 227825 248002 455650 496004 620005 911300 1240010 1612013 2480020 3100025 3224026 6200050 6448052 8060065 12400100 16120130 32240260 40300325 80600650 86924701 161201300 173849402 347698804 434623505 869247010 1130021113 1738494020 2173117525 2260042226 4346235050 4520084452 5650105565 8692470100 11300211130 22600422260 28250527825 56501055650 113002111300