Base | Representation |
---|---|
bin | 110100100111101110… |
… | …0110110000101000100 |
3 | 101210200022102000212111 |
4 | 1221033130312011010 |
5 | 3322412020030200 |
6 | 123525031230404 |
7 | 11110204045351 |
oct | 1511734660504 |
9 | 353608360774 |
10 | 113002111300 |
11 | 43a18822831 |
12 | 19a98218404 |
13 | a86b470420 |
14 | 567dbb9628 |
15 | 2e159570ba |
hex | 1a4f736144 |
113002111300 has 72 divisors (see below), whose sum is σ = 264456089352. Its totient is φ = 41664000000.
The previous prime is 113002111297. The next prime is 113002111309. The reversal of 113002111300 is 3111200311.
It can be written as a sum of positive squares in 12 ways, for example, as 42245047296 + 70757064004 = 205536^2 + 266002^2 .
It is a Harshad number since it is a multiple of its sum of digits (13).
It is not an unprimeable number, because it can be changed into a prime (113002111309) by changing a digit.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 849300 + ... + 973300.
It is an arithmetic number, because the mean of its divisors is an integer number (3673001241).
Almost surely, 2113002111300 is an apocalyptic number.
113002111300 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 113002111300, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (132228044676).
113002111300 is an abundant number, since it is smaller than the sum of its proper divisors (151453978052).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
113002111300 is a wasteful number, since it uses less digits than its factorization.
113002111300 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 124729 (or 124722 counting only the distinct ones).
The product of its (nonzero) digits is 18, while the sum is 13.
Adding to 113002111300 its reverse (3111200311), we get a palindrome (116113311611).
The spelling of 113002111300 in words is "one hundred thirteen billion, two million, one hundred eleven thousand, three hundred".
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