11300213100000 has 288 divisors, whose sum is σ = 40447049473152. Its totient is φ = 2739444800000.

The previous prime is 11300213099969. The next prime is 11300213100047. The reversal of 11300213100000 is 131200311.

It is a super-2 number, since 2×11300213100000² (a number of 27 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (12).

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 1587847 + ... + 5012153.

It is an arithmetic number, because the mean of its divisors is an integer number (140441144004).

Almost surely, 2^{11300213100000} is an apocalyptic number.

11300213100000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 11300213100000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (20223524736576).

11300213100000 is an abundant number, since it is smaller than the sum of its proper divisors (29146836373152).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

11300213100000 is an equidigital number, since it uses as much as digits as its factorization.

11300213100000 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 3424356 (or 3424328 counting only the distinct ones).

The product of its (nonzero) digits is 18, while the sum is 12.

Adding to 11300213100000 its reverse (131200311), we get a palindrome (11300344300311).

The spelling of 11300213100000 in words is "eleven trillion, three hundred billion, two hundred thirteen million, one hundred thousand".