Base | Representation |
---|---|
bin | 1010010001110000111001… |
… | …1100100011110010010011 |
3 | 1111000022001102120112001212 |
4 | 2210130032130203302103 |
5 | 2440121004114322121 |
6 | 40011141535050335 |
7 | 2244264000256622 |
oct | 244341634436223 |
9 | 44008042515055 |
10 | 11300301323411 |
11 | 3667481553a21 |
12 | 13260a80709ab |
13 | 63c7c97c4c29 |
14 | 2b0d1a7136b9 |
15 | 148e3053925b |
hex | a470e723c93 |
11300301323411 has 2 divisors, whose sum is σ = 11300301323412. Its totient is φ = 11300301323410.
The previous prime is 11300301323407. The next prime is 11300301323413. The reversal of 11300301323411 is 11432310300311.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 11300301323411 - 22 = 11300301323407 is a prime.
Together with 11300301323413, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (11300301323413) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5650150661705 + 5650150661706.
It is an arithmetic number, because the mean of its divisors is an integer number (5650150661706).
Almost surely, 211300301323411 is an apocalyptic number.
11300301323411 is a deficient number, since it is larger than the sum of its proper divisors (1).
11300301323411 is an equidigital number, since it uses as much as digits as its factorization.
11300301323411 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 648, while the sum is 23.
Adding to 11300301323411 its reverse (11432310300311), we get a palindrome (22732611623722).
The spelling of 11300301323411 in words is "eleven trillion, three hundred billion, three hundred one million, three hundred twenty-three thousand, four hundred eleven".
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