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1130031103312 = 2470626943957
BaseRepresentation
bin10000011100011011000…
…110100011110101010000
311000000210210212212211101
4100130123012203311100
5122003300430301222
62223043520154144
7144433136615416
oct20343306436520
94000723785741
101130031103312
113a6275109441
12163011168954
138273b7405a7
143c99dacb2b6
151e5dc1c0927
hex1071b1a3d50

1130031103312 has 10 divisors (see below), whose sum is σ = 2189435262698. Its totient is φ = 565015551648.

The previous prime is 1130031103309. The next prime is 1130031103319. The reversal of 1130031103312 is 2133011300311.

It can be written as a sum of positive squares in only one way, i.e., 1097708816656 + 32322286656 = 1047716^2 + 179784^2 .

It is a self number, because there is not a number n which added to its sum of digits gives 1130031103312.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1130031103319) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 35313471963 + ... + 35313471994.

Almost surely, 21130031103312 is an apocalyptic number.

It is an amenable number.

1130031103312 is a deficient number, since it is larger than the sum of its proper divisors (1059404159386).

1130031103312 is an equidigital number, since it uses as much as digits as its factorization.

1130031103312 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 70626943965 (or 70626943959 counting only the distinct ones).

The product of its (nonzero) digits is 162, while the sum is 19.

Adding to 1130031103312 its reverse (2133011300311), we get a palindrome (3263042403623).

The spelling of 1130031103312 in words is "one trillion, one hundred thirty billion, thirty-one million, one hundred three thousand, three hundred twelve".

Divisors: 1 2 4 8 16 70626943957 141253887914 282507775828 565015551656 1130031103312